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Find the sum of the areas under the standard normal curve to the left of z=-2.5 and to the right of z =1 .08

Sagot :

Answer:

P(-2.5<x<1.08) = 0.85372

P(x<-2.5 or x>1.08) = 0.14628

P(x<-2.5) = 0.0062097

P(x>1.08) = 0.14007