Area of Triangle
A∆ = ½bh
where
b = base = 14m
h = height = 12m
solve for Area,
A∆ = ½bh
A∆ = ½(14)(12)
A∆ = 84 m²
Area of Circle,
A of Circle = πr²
where
A of Circle = ?
π = 3.14
r = radius = 4m
Solve for Area,
A of Circle = πr²
A of Circle = 3.14(4)²
A of Circle = 3.14(16)
A of Circle = 50.24 m²
Area Remaining = A∆ - A of Circle
Area Remaining = 84 - 50.24
Area Remaining = 33.76 m²
