PROBLEM
The difference of the sum of (-3) and (+1) and the product of (-10) and (+2) is equal to _____?
SOLUTION
First, we must get the sum of (-3) and (+1).
[tex]( - 3) + ( + 1) = \: ?[/tex]
[tex] \sf{We \: had \: to \: remove \: the \: parenthesis \: then \: solve.}[/tex]
[tex] - 3 + 1 = \green{ - 2}[/tex]
The sum of -3 and 1 is 2.
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Now, we got the sum of (-3) and (1), now we had to get the product of (-10) and (+2)
[tex]( - 10) \times ( + 2) = \: ?[/tex]
[tex]\sf{We \: had \: to \: remove \: the \: parenthesis \: then \: solve.}[/tex]
[tex] - 10 \times 2 = \green{20}[/tex]
The product of -10 and 2 is -20.
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After getting the product, we must get the difference between -20 and -2.
[tex] - 20 - ( - 2) = \: ?[/tex]
When there a (-) in front of an expression in a parenthesis, change the sign of it.
[tex] - 20 - 2 = \: ?[/tex]
Now solve.
[tex] - 20 - 2 = \blue{18}[/tex]
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- Therefore, the difference of the sum of (-3) and (+1) and the product of (-10) and (+2) is equal to 18.
[tex]_______________________________________[/tex]
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