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ELLAMONJE63IN
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Let a be the shorter leg of a 30°-60°-90° triangle. Find sin 30°, cos 30°, tan 30°, sec 30°, csc 30° and cot 30°.​

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Answer:

[tex]Sin \: 30° = \frac{1}{2} [/tex]

[tex]Cos \: 30° = \frac{ \sqrt{3} }{2} [/tex]

[tex]Tan \: 30° = \frac{1}{ \sqrt{3} } [/tex]

[tex]Sec \: 30° = \frac{ \sqrt[2]{3} }{2} [/tex]

[tex]Csc \: 30° = 2[/tex]

[tex]Cot 30° = \sqrt{3} [/tex]

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