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POJARASLYNSHERIN
Answered

a gas occupies 12.3 liters at a pressure of 40.0 kpa. what is the volume when the pressure is increased to 60.0 kpa?

Pahelp po. ​

Sagot :

LYK20IN

Answer:

400.0

sana makatulong hindi ko pa kasi alam yan

ZYRAONGCAL4IN

8.2L

Explanation:

Formula: Boyle's Law (V¹P¹=V²P²)

Variables:

V¹=12.3L

P¹=40.0 kpa

V²=?

P²=60.0 Kpa

:SOLUTION:

V²=(12.3 L) (40.0 kpa)=492÷60.0 kapa=8.2

yan po sana makatulong❤

alam ko po kasi yan

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