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A weightlifter lifts a set of weights a vertical distance of 2.00m. If a constant net force of 350N is exerted on the weights, what is the net work done on the weights?

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KOURTNEYKIN KOURTNEYKIN

W = Fs

F = force (350 N)
s = displacement (2 m)

W = 350 . 2
= 700 J

The work exerted in the weights is 700 J.

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