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a boy tosses a coin upward with a velocity of +14.7m/s. find （a）the maximum height reached by the coin,（b）time of flight and the （c）velocity when the coin returns to the hand.（d）suppose the boy failed to catch the coin and the coin goes to the ground,with what velocity will it strike the ground？the boy s hand is 0.49m above the ground

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VILMASUELO45IN

Answer:

a) Use the formula; V^2=Vo^2=2g(y-yo)

cancel V^2 and yo (because it is zero)

-V0^2/2g=2gy/2g <-- Cancel 2g

y=-Vo/2g=-(14.7 m/s2)/2(-9.8m/s^2)

y=11.04m

b)t=2y/Vo=2(11.04m)/14.7 m/s

t=1.5s

t^2(1.5)(2)

=3s

c)V^2=(2g)(yo)

=2(-9.8 m/s^2)(-11.04)

V^2= <SQUARE-ROOT>216.38

=-14.71 m/s

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