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what is the area of the trapezoid whose height is 3 cm the shorter base is threesome and the longer busy is 5 cm ?​

Sagot :

Answer

A = 1/2 (b1 + b2) h
A = 1/2 ( 3cm + 5cm ) (3cm)
A = 1/2 (8cm) (3cm)
A = 24sq.cm / 2
A = 12sq.cm

Hope it helps