Answer:
301 kj of energy
heat required to melt the ice to water at 0oC
heat required to warm the water from 0oC to 100oC
heat required to vaporize the water to vapor at 100oC
100.g x (334j)/(1g)= 33400j
100. g x (4.184j)/(1oC•g) x 100oC = 41800 J
100.g x (2260J)/(1g)= 226000 J
33400 J + 41800 J + 226
= 301 kJ
