Sagot :
Given:
mass of solute = 0.0908 g
volume of solution = 0.500 L
solute: KMnO₄
Required:
molarity
Solution:
Step 1: Calculate the molar mass of solute.
molar mass of solute = (39.10 g/mol × 1) + (54.94 g/mol × 1) + (16.00 g/mol × 4)
molar mass of solute = 158.04 g/mol
Step 2: Calculate the number of moles of solute.
[tex]\text{moles of solute} = \frac{\text{mass of solute}}{\text{molar mass of solute}}[/tex]
[tex]\text{moles of solute} = \frac{\text{0.0908 g}}{\text{158.04 g/mol}}[/tex]
moles of solute = 0.000574538 mol
Step 3: Calculate the molarity of solution.
[tex]\text{molarity} = \frac{\text{moles of solute}}{\text{volume of solution}}[/tex]
[tex]\text{molarity} = \frac{\text{0.000574538 mol}}{\text{0.500 L}}[/tex]
[tex]\boxed{\text{molarity = 0.00115 M}}[/tex]
[tex]\\[/tex]
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