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. If a varies inversely as the square of b and a =
-3 when b = 4, find a when b= 36.​


Sagot :

GIVEN

[tex] \\ [/tex]

If a varies inversely as the square of b and a = -3 when b = 4, find a when b= 36.

[tex] \\ a = \frac{k}{ {b}^{2} } \\ \\ [/tex]

Evaluate the values

[tex] \\ - 3 = \frac{k}{( {4}^{2} )} \\ \\ [/tex]

Square 4

[tex] \\ - 3 = \frac{k}{16} \\ \\ [/tex]

Multiply 16 to both sides

[tex] \\ (16)( - 3) = \frac{k}{16} (16) \\ \\ [/tex]

Cancel both 16 from the right side then multiply 16 to -3

[tex] \\ (16)( - 3) = \frac{k}{ \cancel{16} } (\cancel{16}) \\ \\ \large \boxed{k = - 48} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ [/tex]

Finding the value of a when b= 36. Use the k value from the first problem.

[tex] \\ a = \frac{k}{ {b}^{2} } \\ \\ [/tex]

Evaluate values

[tex] \\ a = \frac{ - 48}{( {36}^{2} ) } \\ \\ [/tex]

Square 36

[tex] \\ a = \frac{ - 48}{1296} \\ \\ [/tex]

Simplify

[tex] \\ \tt{ans.} \implies \large\green{ \boxed{ \bold{a = \frac{ - 1}{27} }}} \\ \\ \\ [/tex]

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