Sagot :
GIVEN
[tex] \\ [/tex]
If a varies inversely as the square of b and a = -3 when b = 4, find a when b= 36.
[tex] \\ a = \frac{k}{ {b}^{2} } \\ \\ [/tex]
Evaluate the values
[tex] \\ - 3 = \frac{k}{( {4}^{2} )} \\ \\ [/tex]
Square 4
[tex] \\ - 3 = \frac{k}{16} \\ \\ [/tex]
Multiply 16 to both sides
[tex] \\ (16)( - 3) = \frac{k}{16} (16) \\ \\ [/tex]
Cancel both 16 from the right side then multiply 16 to -3
[tex] \\ (16)( - 3) = \frac{k}{ \cancel{16} } (\cancel{16}) \\ \\ \large \boxed{k = - 48} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ [/tex]
Finding the value of a when b= 36. Use the k value from the first problem.
[tex] \\ a = \frac{k}{ {b}^{2} } \\ \\ [/tex]
Evaluate values
[tex] \\ a = \frac{ - 48}{( {36}^{2} ) } \\ \\ [/tex]
Square 36
[tex] \\ a = \frac{ - 48}{1296} \\ \\ [/tex]
Simplify
[tex] \\ \tt{ans.} \implies \large\green{ \boxed{ \bold{a = \frac{ - 1}{27} }}} \\ \\ \\ [/tex]
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