Sagot :
Answer:
a. Total outcomes
S={1,2,3,4,5,6}
Even numbers= 2,4,6
Multiple of 3= 3,6
So, favourable events ={2,3,4,6}
P= n(E)/n(S)
= 4/6
=2/3
B.
Total outcomes
S={1,2,3,4,5,6}
Multiple of 2= 2,4,6
Multiple of 3= 3,6
So, favourable events ={2,3,4,6}
P= n(E)/n(S)
= 4/6
=2/3
C.
Total outcomes
S= {1,2,3,4,5,6}
Multiple of 2= 2,4,6
Odd= 1,3,5
Favourable events= { 1,2,3,4,5,6}
P= n(E)/n(S)
= 6/6
=1