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UCANTSEEMEEIN
Answered

1. There are five white balls, eight red balls, seven yellow balls and four green balls in a container. A ball is chosen at random. What is the probability of choosing neither white nor green.

A. 5/72
B. 5/24
C. 13/24
D. 5/8

With explanation please thank you I will brainliest mark

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KILLUAZOLDYC017IN

1. There are five white balls, eight red balls, seven yellow balls and four green balls in a container. A ball is chosen at random. What is the probability of choosing neither white nor green.  

A. 5/72

B. 5/24

C. 13/24

D. 5/8

Answer:

5 white balls + 8 red balls + 7 yellow balls + 4 green balls = 24 balls. So, 4.16% for per ball. ∵ 5 white balls + 4 green balls = (5+4)*4.16% = %. ∴ The probability for choosing neither white nor green balls = 37.5%

Step-by-step explanation:

JARVEYREIJANIN

Answer:

  1. B

Step-by-step explanation:

A ball is chosen at random from a container of 5 white balls, 8 red balls, 7 yellow balls and 4 green balls. We need to determine the probability of choosing either red or white. Thus, there are 24 number of balls in the container

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