Sagot :
Answer:
1. 3x=28+x; x=14
2. let A for Anthony
B for Benson
R for Robert
A= 5+B
R= B-3
A+B+R=50
substitute
(5+B)+(B-3)+B=50
B=16
then substitue B from 1st and 2nd equation
you will get A=21, R= 13
3. let r for ronald n j for john
r+j=80
j=4r
substitute j
r+4r =80
r=16
j=4(16) =64
4. [(5-n)+1/(n)+1] = 2/3
(5-n)3=n(2)
15-3n=2n
15=5n
n=3