Given:
[tex]P_{1} = \text{1.5 atm}[/tex]
[tex]T_{1} = \text{26°C + 273 = 299 K}[/tex]
[tex]T_{2} = \text{98°C + 273 = 371 K}[/tex]
Unknown:
[tex]P_{2}[/tex]
Solution:
[tex]\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}[/tex]
[tex]P_{2} = P_{1} × \frac{T_{2}}{T_{1}}[/tex]
[tex]P_{2} = \text{1.5 atm} × \frac{\text{371 K}}{\text{299 K}}[/tex]
[tex]\boxed{P_{2} = \text{1.9 atm}}[/tex]
[tex]\\[/tex]
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