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Plss po pa help po sa math problem plsss

Plss Po Pa Help Po Sa Math Problem Plsss class=

Sagot :

Answer:

1. 39 dm²

Solution:

A = LW – LW

A = (10 dm × 6dm) – (7dm × 3dm)

A = 60 dm² – 21 dm²

A = 39 dm²

2. 90 m²

Solution:

A =

[tex] \frac{a + b}{2}h + s {}^{2} [/tex]

A =

[tex] \frac{12m + 6m}{2} (6m) +( 6m) {}^{2} [/tex]

A = 9m(6m) + 36m²

A = 54 m² + 36m²

A = 90 m²

3. 100.26 cm²

Solution:

A =

[tex]lw + \ \frac{\pi \: r {}^{2} }{2} + \frac{\pi \: r {}^{2} }{2} [/tex]

A = (12cm × 6cm) + 3.14(3 cm)²/2 + 3.14(3 cm)²/2

A = 72 cm² + 14.13 cm² +14.13 cm²

A = 100.26 cm²

4. 49.04 m²

Solution:

A =

[tex]\pi \: r {}^{2} - s {}^{2} [/tex]

A = 3 14(6m)² – (8m)²

A = 3.14(36 m²) – 64 m²

A = 113.04 m² – 64 m²

A = 49.04 m²

5. 72 m²

Solution:

A = LW – 1/2bh

A = (13 m × 8m) – 1/2(8m × 8m)

A = 104 m² – 1/2(64 m²)

A = 104 m² – 32 m²

A = 72 m²