[tex] \large\underline \mathcal{{QUESTION:}}[/tex]
The diameter of a circle has length 12. The center is at (−2,5).
[tex]\\[/tex]
[tex] \large\underline \mathcal{{SOLUTION:}}[/tex]
- Diameter = 12 so Radius = 6
Given that n= -2 , k= 5 , r= 6
[tex]\\[/tex]
Substitute the values to the standard form of a circle:
[tex]\sf{(x-h)^2+(y-k)^2=r^2}[/tex]
[tex]\sf{(x-(-2))^2+(y-5)^2=6^2}[/tex]
[tex]\boxed{\sf{(x+2)^2+(y-5)^2=36}}[/tex]
[tex]\\[/tex]
[tex] \large\underline \mathcal{{ANSWER:}}[/tex]
- The equation is (x+2)²+(y-5)²=36
