[tex] \large\underline \mathcal{{QUESTION:}}[/tex]
find the length of the longer leg of a 30-60-90 triangle if the length of the shorter leg is 5√3?
[tex]\\[/tex]
[tex] \large\underline \mathcal{{SOLUTION:}}[/tex]
Remember
- Shorter = Longer ÷ √3
- Longer = Shorter × √3
- Hypothenus = Shorter × 2
[tex]\\[/tex]
[tex]\sf{Longer=Shorter\times\sqrt{3}}[/tex]
[tex]\sf{Longer=5\sqrt{3}\times\sqrt{3}}[/tex]
[tex]\sf{Longer=5}[/tex]
[tex]\\[/tex]
[tex] \large\underline \mathcal{{ANSWER:}}[/tex]
- The longer leg measures 5 units
