Answer:
Given polynomial is x²-12x+20
Given polynomial is x²-12x+20On comparing with ax²+bx+c then we have
Given polynomial is x²-12x+20On comparing with ax²+bx+c then we havea=1,b=-12,c=20
Given polynomial is x²-12x+20On comparing with ax²+bx+c then we havea=1,b=-12,c=20we know that
Given polynomial is x²-12x+20On comparing with ax²+bx+c then we havea=1,b=-12,c=20we know thatsum of the zeroes =-b/a
Given polynomial is x²-12x+20On comparing with ax²+bx+c then we havea=1,b=-12,c=20we know thatsum of the zeroes =-b/a=>-(-12)/1
Given polynomial is x²-12x+20On comparing with ax²+bx+c then we havea=1,b=-12,c=20we know thatsum of the zeroes =-b/a=>-(-12)/1=>12
Given polynomial is x²-12x+20On comparing with ax²+bx+c then we havea=1,b=-12,c=20we know thatsum of the zeroes =-b/a=>-(-12)/1=>12Sum of the zeroes =12
Step-by-step explanation:
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