Answer:
exterior angle of a triangle = sum of the two opposite interior angles
exterior angle of a triangle = sum of the two opposite interior angleslet the second interior angle be x
exterior angle of a triangle = sum of the two opposite interior angleslet the second interior angle be xThen,
exterior angle of a triangle = sum of the two opposite interior angleslet the second interior angle be xThen,130 = 60 + x
exterior angle of a triangle = sum of the two opposite interior angleslet the second interior angle be xThen,130 = 60 + xx = 130 - 60
exterior angle of a triangle = sum of the two opposite interior angleslet the second interior angle be xThen,130 = 60 + xx = 130 - 60x = 70
exterior angle of a triangle = sum of the two opposite interior angleslet the second interior angle be xThen,130 = 60 + xx = 130 - 60x = 70Now,
exterior angle of a triangle = sum of the two opposite interior angleslet the second interior angle be xThen,130 = 60 + xx = 130 - 60x = 70Now,third angle of the triangle = 180 - (70 + 60)
exterior angle of a triangle = sum of the two opposite interior angleslet the second interior angle be xThen,130 = 60 + xx = 130 - 60x = 70Now,third angle of the triangle = 180 - (70 + 60)= 180 - 130
exterior angle of a triangle = sum of the two opposite interior angleslet the second interior angle be xThen,130 = 60 + xx = 130 - 60x = 70Now,third angle of the triangle = 180 - (70 + 60)= 180 - 130= 50
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