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what is the general equation of the circle (x-6)2+(y-6)2=49​

Sagot :

Answer:

x^2+y^2-12x-12y-13=0

Step-by-step explanation:

(x-6)^2+(y-6)^2=49

x^2-12x+36x+y^2-12y+36=49

x^2+y^2-12x-12y+36-49=0

x^2+y^2-12x-12y-13=0

General equation: x^2+y^2-12x-12y-13=0

In the equation, D=-12,E=-12,and F=-13