Answer:
Given :
n = 8 (total letters consist of the eor OLONGAPO)
r = 3(total letters(O) with repetition)
Solution :
nPr = 8!
3!
[tex] = \frac{8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1}{3 \times 2 \times 1} [/tex]
[tex] = \frac{40320}{6} [/tex]
[tex] = 6720[/tex]
Therefore there are 6,720 permutation
