Mike needs 30% to pass. If he scored 212 marks and falls short by 13 marks, what was the maximum marks he could have got
Solution:
If Mike had scored 13 marks more, he could have scored 30%
Therefore, Mike required 212 + 13 = 225 marks
Let the maximum marks be m.
Then 30 % of m = 225
(30/100) × m = 225
m = (225 × 100)/30
m = 22500/30
m = 750
