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A 200 ml sample of a gas at 20°C is to be cooled at constant pressure until its volume becomes 150mL. What will be the new temperature of the gas?


Sagot :

Given:

[tex]V_{1} = \text{200 mL}[/tex]

[tex]T_{1} = \text{20°C + 273 = 293 K}[/tex]

[tex]V_{2} = \text{150 mL}[/tex]

Unknown:

[tex]T_{2}[/tex]

Solution:

[tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}[/tex]

[tex]T_{2} = T_{1} × \frac{V_{2}}{V_{1}}[/tex]

[tex]T_{2} = \text{293 K} × \frac{\text{150 mL}}{\text{200 mL}}[/tex]

[tex]\boxed{T_{2} = \text{220 K}}[/tex]

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