Answer:
11 m
Explanation:
[tex]vf(final \: velocity) = 3.0mps \\ vi(initial \: velocity) = 15mps \\ g = 9.81mp {s}^{2} \: (acceleration \: due \: to \: gravity)[/tex]
[tex] y = \frac{ {vf}^{2} - \: {vi}^{2} }{2g} \\ y = \frac{ {(3mps)}^{2} - {(15mps)}^{2} }{2( - 9.81mp{s}^{2} )} \\ y = 11m[/tex]
