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11. The length of a rectangular lot is 4 meters longer than its width. If the perimeter is 68
meters, what are the dimensions of the lot?
A. 30 m by 38 m
C. 32 m by 36 m
B. 31 m by 37 m
D. 33 m by 35 m​

Sagot :

AGBOIIIN

[tex] \large\underline \bold{{GIVEN}}[/tex]

  • Length = x+4
  • Width = x
  • Perimeter = 68

[tex] \large\underline \bold{{SOLUTION}}[/tex]

Remember the formula in finding the perimeter:

[tex]\longmapsto\sf{P=2(L+W)}[/tex]

Substitute the given expressions and solving for the dimensions:

[tex]\longmapsto\sf{P=2(x+4+x)}[/tex]

[tex]\longmapsto\sf{68=2x+4}[/tex]

[tex]\longmapsto\sf{68-4=2x}[/tex]

[tex]\longmapsto\sf{64=2x}[/tex]

[tex]\longmapsto\sf{32=x}[/tex]

Now, Substitute again the value of x to get the dimensions:

[tex]\textrm{Length = x+4 = 32+4 = \boxed{36meters}}[/tex]

[tex]\textrm{Width = x = \boxed{32meters}}[/tex]

[tex] \large\underline{ \bold{ANSWER}}[/tex]

  • OPTION C (32m by 36m)

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