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two charged objects have a repulsive force of 0.080 N.if the distance separating the objects is doubled then what is the new force?​

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C41992IN

Answer:

new force= 0.02 N

Step-by-step explanation:

F = kq1q2/d²

(assumed that their charges remain unchanged)

F1(d1)² = F2(d2)²

such that d2=2(d1)

0.08(d1)² = F2( 2*d1)²

0.08(d1)² = F2(4*( d1²)

cancel both (d1)²

F2= 0.08/4

F2 = 0.02 or 2 X 10^(-2) N

(sana nakatulong)

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