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Answer each permutation problem completely with solution.
1. In a certain general assembly, three major prizes are at stake. In how many ways can the first,second, and third prizes be drawn from a box containing 20 names?
2. Eight basketball teams are competing for the top 4 standings to move up to the semi-finals. Find number of possible ways that they will be in first to 4th rank.
(Nonsense answer=reported)​


Sagot :

Answer:

1. P(n,r) = P(20,3)  

= 20!/(20−3)!

= 6,840 ways

2. P(n,r) = P(8,4)

= 8!/(8−4)!

= 1,680 ways

If you have any questions, feel free to send a message.

Answer:

1.6480

2.1680

Step-by-step explanation:

it seems to me that it is tha correct answer

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