Sagot :
• Problem:
When an integer is divided by 25 and the result is multiplied by 5 more than +3, the result is 10 more than twice seven. What is the integer?
• Solution:
We need to solve for the value of x.
[tex] \large\boxed{ \begin{array}{} \tt \big( \frac{x}{25} \big) \big(5 \big) + 3 = 10 + 2(7) \\ \tt \frac{5}{25}x + 3 = 10 + 14 \\ \tt \frac{x}{5} + 3 = 24 \\ \tt \frac{x}{5} = 24 - 3 \\ \tt \frac{x}{5} = 21 \\ \tt x = 21(5) = 105\end{array}}[/tex]
Try to check it by substituting the value of x to the first equation. If you happen to solve for the same value on the left and right of the equation, then you 105 is the correct answer.
• Answer:
The integer is 105.