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A 1400-kg car is moving at a speed of 25 m/s. How much kinetic energy does the car have?

Sagot :

[tex] \large{ \implies{ \underline{ \bold{Question:}}}}[/tex]

A 1400-kg car is moving at a speed of 25 m/s. How much kinetic energy does the car have?

[tex] \large{ \implies{ \underline{ \bold{Unit:}}}}[/tex]

The unit for kinetic energy or (KE) is the joules.

1 kg.m²/ = 1 joule

[tex] \large{ \implies{ \underline{ \bold{Given:}}}}[/tex]

M = 1,400kg

V = 25 m/s

KE = ?

Formula: KE = ½ mv²

[tex] \large{ \implies{ \underline{ \bold{Solution:}}}}[/tex]

KE = ½ (1,400kg) × (25m/s)²

KE = (700kg) × (25m/s)²

KE = (700kg) × (625m²/s²) (since 1 kg.m²/s² = 1 joule)

[tex] \small{\boxed{\bold{KE \: = 437,500 \: j}}}[/tex]

[tex] \large{ \implies{ \underline{ \bold{Answer:}}}}[/tex]

The kinetic energy of 1,4000 kg and 25 m/s, there is the car of

[tex] \color{red}{\boxed{\boxed {\boxed{\bold{KE \: = 437,500 \: j}}}}}[/tex]

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Problem

A 1400-kg car is moving at a speed of 25 m/s. How much kinetic energy does the car have?

[tex] \large{\tt{GIVEN}}[/tex]

M = 1,400kg

V = 25 m/s

KE = ?

Formula: KE = ½ mv²

[tex] \large{ \sf{Solution}}[/tex]

KE = ½ (1,400kg) × (25m/s)²

KE = (700kg) × (25m/s)²

KE = (700kg) × (625m²/s²)

(since 1 kg.m²/s² = 1 joule)

[tex] \large{ \sf{KE}} = \large{\sf{437,500 \: j }}[/tex]

[tex] \large{ \sf{Answer}}[/tex]

[tex] \large{\sf{KE \:} = \boxed{\tt{437,500 \: j}}}[/tex]