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MIZUKIGUNTHEIN
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if three arithmetic means are inserted between 9 and 1 find the third arithmetic mean​

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KEURISTINAIN
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First term =-15

Second term is 9

Tn=a×(n-1)d

If you insert 3 arithmatic means between them 9 WIILL be T5 of AP

T5=T1+(5-1)×d

9=T1+4d

9=-15+4d

4d=24

d=6

a=--15 d=6

The terms of AP are

-15 -15+6 - 15 +2×6 -15 +3× 6 -15+4×6

-15 -9 -3 3 9

First AM is --9

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