Answer:
The average loan of an employee is Php18,200. If the debt is normally distributed with a standard deviation of Php6,150, find the probabilities;
a. that the employee owes more than Php20,000.
z= 20,000-18,200/6,150
=1.8/6,150
=0.29
=0.6141
b. that the employee owes between Php10,000 and Php25,000.
z= 10,000-18,200/6,150 z= 25,000-18,200/6,150
= -8.2/6,150 =6.8/6,150
= -1.33 =0.65
z =0.0918 z=0.7422
0.0918-0.7422= -0.6504
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Step-by-step explanation: