👤

Which of the following sub levels is properly designated?
a. 1p2
b. 2s2
c. 3d11
d. 3df


Sagot :

Answer:

b. 2s²

Explanation:

The numerical coefficient in 2s² is 2. This is the value of n. Since n = 2, the possible values for l are 0 (s-orbital) and 1 (p-orbital). Hence, 2s orbital exists.

The exponent in 2s² is 2. Since the orbital is an s-orbital, it can contain a maximum of 2 electrons. Hence, 2s satisfies this condition.

Since 2s orbital exists and it contains two electrons, therefore, 2s² is properly designated.

#CarryOnLearning