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. Given a circle with center (5, 1) and a point on the circle (8,-2).​

Sagot :

SOLUTION

Given the center (5,1) ,we then substitute the the givens to the standard form of a circle.

Substituting the center to the equation

  • (x-h)²+(y-k)²=r²
  • (x-5)²+(y-1)²=r²

Now, all we need to do is to find the value of the radius.

Substituting the point to the equation.

  • (8,-2) , x = 8 , y = -2
  • (x-5)²+(y-1)²=r²
  • (8-5)²+(2-1)²=r²
  • (3)²+(1)²=r²
  • 9+1 = r²
  • 10 = r²

Summing up the equation we get:

  • (x-5)²+(y-1)²=10

ANSWER

  • (x-5)²+(y-1)²=10

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