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Divide this using the long division method, show your solution

(n³+3n²+5n-9) ÷ (n-1)

improper answers will be reported


Sagot :

[tex]( {n}^{2} + 3n {}^{2} + 5n - 9) \div (n - 1)[/tex]

COLLECT like terms

[tex](4n {}^{2} + 5n - 9) \div (n - 1)[/tex]

WRITE the division as a fraction

[tex] \frac{4n {}^{2} + 5n - 9}{n - 1} [/tex]

write 5n as difference

[tex] \frac{4n {}^{2} + 9n - 4n - 9}{n - 1} [/tex]

factor out n from the expression

[tex] \frac{n \times (4n + 9) - 4n - 9}{ n - 1} [/tex]

factor out the negative sign from the expression

[tex] \frac{n \times (4n + 9) - (4n + 9)}{n - 1} [/tex]

factor out 4n + 9 from the expression

[tex] \frac{(4n + 9) \times (n - 1)}{n - 1} [/tex]

reduce the fraction with n-1

[tex]4n + 9[/tex]

sorry ang tagal [totoo ang mga answer]