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Find the dimensions of a rectangle when the length is 10 inches more than its width and the area is 1200 square inches

Sagot :

Answer:

Therefore,

W = x

L = x + 10

WL = 1200  

x (x + 10) = 1200

x^2 + 10x = 1200

x^2 + 10x - 1200 = 0

(x - 30)(x + 40)

x = -40

x = 30

Since, there is no negative dimension. Let's use x = 30

Thus,  

W = 30

L = 30 + 10 = 40

LW = 1200

(30)(40) = 1200

Step-by-step explanation:thanks me and mark brainliest