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1. The slope of the line whose y-intercept is -2 and passing through the point (6, 0) is​

Sagot :

SOLUTION

  • y = mx + b

m = slope and b = y-intercept

  • y = x - 2

Now , given that (6,0) is a point that passes through the line. We then substitute the value of the point to the equation

  • y = x - 2
  • 0 = m(6)-2
  • 0 = 6m -2
  • 2 = 6m
  • 2/6 = m
  • 1/3 = m

ANSWER

  • The slope is 1/3

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