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2. What is empirical formula of a compound which consists of 89.14% Au and 10.80% of O?​

Sagot :

Answer:

In order to find a compound's empirical formula you must determine the smallest whole number ratio that exists between its constituent elements.

In this case, your unknown compound is said to contain only gold,  

Au

, and oxygen,  

O

. The compound's percent composition essentially tells you how many grams of each constituent element you get per  

100 g

of compound.

In this case, a  

100-g

sample of this unknown compound will contain  

89.14 g

of gold and  

10.86 g

of oxygen.

This means that you can use the molar mass of each element to find how many moles you get in that  

100-g

sample. You will thus have

For Au:  

89.14

g

1 mole Au

196.97

g

=

0.45256 moles Au

For O:  

10.86

g

1 mole O

15.9994

g

=

0.67876 moles O

To find the mole ratio that exists between the two elements, divide both values by the smallest one. This will get you

For Au:

0.45256

moles

0.45256

moles

=

1

For O:  

0.67876

moles

0.45256

moles

=

1.4998

1.5

Now, it's important to remember that you're looking for the smallest whole number ratio here, which means that you're going to have to multiply both values by  

2

to get

(

Au

1

O

1.5

)

2

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

a

a

Au

2

O

3

a

a

−−−−−−−−−−

Explanation: