Sagot :
Answer:
[tex]x = 18[/tex]
Step-by-step explanation:
[tex] \sqrt{2x} = \sqrt{x + 18} [/tex]
[tex] {}^{2} ( \sqrt{2x} = \sqrt{x + 18} ) {}^{2} [/tex]
[tex]2x = x + 18[/tex]
[tex]2x - x = 18[/tex]
[tex]x = 18[/tex]
Answer:
[tex]x = 18[/tex]
Step-by-step explanation:
[tex] \sqrt{2x} = \sqrt{x + 18} [/tex]
[tex] {}^{2} ( \sqrt{2x} = \sqrt{x + 18} ) {}^{2} [/tex]
[tex]2x = x + 18[/tex]
[tex]2x - x = 18[/tex]
[tex]x = 18[/tex]