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the square root of twice a number is equal to the square root of 18 more than the number. find the number

Sagot :

Answer:

[tex]x = 18[/tex]

Step-by-step explanation:

[tex] \sqrt{2x} = \sqrt{x + 18} [/tex]

[tex] {}^{2} ( \sqrt{2x} = \sqrt{x + 18} ) {}^{2} [/tex]

[tex]2x = x + 18[/tex]

[tex]2x - x = 18[/tex]

[tex]x = 18[/tex]