Sagot :
Answer:
59.137 g of aluminum
Explanation:
there is one mole of AI203 for every 2 moles of water .First find the formula mass for AI203 which is 101.961 g per mole and multiply it by the number of moles (.58).58x101. 961=59.137 g of aluminum
Answer:
59.137 g of aluminum
Explanation:
there is one mole of AI203 for every 2 moles of water .First find the formula mass for AI203 which is 101.961 g per mole and multiply it by the number of moles (.58).58x101. 961=59.137 g of aluminum