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How many grams of aluminum are in 0.58 moles of Al2O3-2H2O?


Sagot :

Answer:

59.137 g of aluminum

Explanation:

there is one mole of AI203 for every 2 moles of water .First find the formula mass for AI203 which is 101.961 g per mole and multiply it by the number of moles (.58).58x101. 961=59.137 g of aluminum

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