[tex] \large \bold{ANSWER:} [/tex]
[tex] \begin{array}{l} \begin{aligned} A.\quad &\textsf{Given: } \angle 1 \cong \angle 2 \textsf{ and } \angle 2 \cong \angle 3 \\ & \textsf{Prove: }\angle 1 \cong \angle 3 \\ & \textsf{Proof: } \end{aligned} \\ \\ \footnotesize \begin{array}{| l | l |} \hline \:\:\: \bold{Statements} & \quad\qquad\bold{Reasons} \\ \hline \negthickspace\!{\begin{array}{l} 1.\: \angle 1 \cong \angle 2 \\ \quad\! \angle 2 \cong \angle 3 \end{array}} & \textsf{Given} \\ \hline \negthickspace\!{\begin{array}{l} 2.\: \textsf{m}\angle 1 = \textsf{m}\angle 2 \\ \quad \!\textsf{m}\angle 2 = \textsf{m}\angle 3 \end{array}} & \textsf{Definition of Congruent Angles} \\ \hline 3.\: \textsf{m}\angle 1 = \textsf{m}\angle 3 & \textsf{Transitive Property of Equality} \\ \hline 4.\:\: \angle 1 \cong \angle 3 & \textsf{Definition of Congruent Angles} \\ \hline \end{array} \end{array} [/tex]
[tex] \begin{array}{l} \begin{aligned} B.\quad &\textsf{Given: } \angle T \textsf{ is an angle.} \\ &\textsf{Prove: } \angle T \cong \angle T \\ &\textsf{Proof:} \end{aligned} \\ \\ \footnotesize \begin{array}{| l | l |} \hline \:\:\bold{Statements} & \quad\qquad\bold{Reasons} \\ \hline 1.\: \angle T\textsf{ is an angle.} & \textsf{Given} \\ \hline 2.\: \textsf{m}\angle T = \textsf{m}\angle T & \textsf{Reflexive Property of Equality} \\ \hline 3.\: \angle T \cong \angle T & \negthickspace\! {\begin{array}{l} \textsf{Definition of Congruent Angles,} \\ \textsf{Reflexive Property of Congruence} \end{array}} \\ \hline \end{array} \end{array} [/tex]
[tex] \blue{\mathfrak{\#CarryOnLearning}} [/tex]
