The answer is 14.
[tex] \sqrt{2 + x} = 4[/tex]
Square both sides of the equation to remove the radical sign.
[tex] { \sqrt{2 + x} }^{2} = {4}^{2} [/tex]
[tex]x + 2 = 16[/tex]
Then transpose 2 to the right side to find the value of x. This will make 2 change its sign to negative.
[tex]x = 16 - 2[/tex]
Subtract the numbers and you'll find x.
[tex]x = 14[/tex]
please mark me the brainliest hehe
