Sagot :
Answer:
2. B. 6
3. D. 8 and 3
Step-by-step explanation:
2. B. 6
[tex] \sqrt{2x - 3} = 3[/tex]
[tex] {}^{2} ( \sqrt{2x - 3} = 3) {}^{2} [/tex]
[tex]2x - 3 = 9[/tex]
[tex] 2x = 9 + 3[/tex]
[tex] 2x = 12[/tex]
[tex] \frac{ 2x}{ 2} = \frac{12}{ 2} [/tex]
[tex]x = 6[/tex]
3. D. 8 and 3
[tex] \sqrt{3x - 8} = x - 4[/tex]
[tex] {}^{2} ( \sqrt{3x - 8} = x - 4) {}^{2} [/tex]
[tex]3x - 8 = (x - 4) {}^{2} [/tex]
[tex] {x}^{2} - 3x + 8 - 16 = 0[/tex]
[tex] 3x - 8 = {x}^{2} - 4x - 4x + 16[/tex]
[tex]3x - 8 = {x}^{2} - 8x + 16[/tex]
[tex] {x}^{2} - 8x - 3x + 16 + 8[/tex]
[tex] {x}^{2} - 11x + 24[/tex]
[tex]x - 8 \\ x - 3[/tex]
[tex]x = 8 \\ x = 3[/tex]