Sagot :
Answer:
6x−2x
2
−1=8
6x−2x
2
−1−8=0
{ - 2x}^{2} + 6x - 9 = 0−2x
2
+6x−9=0
since first term is ≠ 0 . . .
\begin{gathered} - 1( { - 2x}^{2} + 6x - 9 = 0) \\ \\ {2x}^{2} - 6x + 9 = 0\end{gathered}
−1(−2x
2
+6x−9=0)
2x
2
−6x+9=0
Answer:
6x−2x
2
−1=8
6x−2x
2
−1−8=0
{ - 2x}^{2} + 6x - 9 = 0−2x
2
+6x−9=0
since first term is ≠ 0 . . .
\begin{gathered} - 1( { - 2x}^{2} + 6x - 9 = 0) \\ \\ {2x}^{2} - 6x + 9 = 0\end{gathered}
−1(−2x
2
+6x−9=0)
2x
2
−6x+9=0