Sagot :
Since common ratio is 1/3 , less than one. The series would converge and its sum can be found out by using the
a
1
−
r
where a is the first term and r is the common ratio. The sum would be
3
1
−
1
3
=
9
2
a
1
−
r
where a is the first term and r is the common ratio. The sum would be
3
1
−
1
3
=
9
2