Answer:
vote and follow
the values are -2, and 3
[tex] {3y}^{2} - 3y - 18 = 0 \\ (3y + 6)(y - 3) = 0 \\ \\ 3y + 6 = 0 \\ 3y = - 6 \\ y = - 2 \\ \\ y - 3 = 0 \\ y = 3[/tex]
Step-by-step explanation:
checking
[tex]3 {y}^{2} - 3y - 18 = 0 \\ 3( { - 2)}^{2} - 3( - 2) - 18 =0 \\ 3(4) + 6 - 18 = 0 \\ 12 + 6 - 18 = 0 \\ 0 = 0[/tex]
[tex]3 {y}^{2} - 3y - 18 = 0 \\ 3( {3)}^{2} - 3( 3) - 18 =0 \\ 3(9) - 9 - 18 = 0 \\ 27 - 9 - 18 = 0 \\ 0= 0[/tex]
