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Answered

A small light bulb is connected to a 9 V battery and draws 4 A of current. What is the net resistance of the bulb?

Sagot :

MSKLYCHEZ0110IN

Answer:

2.25 Ω

Explanation:

Using Ohm's law:

V=IR

R = [tex]\frac{V}{I}[/tex]

[tex]R = \frac{9V}{4A}[/tex]

R = 2.25 Ω