PERIMETER OF A TRIANGLE
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» Sides of the triangle.
- (2x² + 7) cm
- (3x² - 2x) cm
- (x² + 12x - 5) cm
» Formula.
[tex]\sf \large \blue{Perimeter_∆ = Side_1 + Side_2 + Side_3}[/tex]
» Find the perimeter of the triangle.
[tex] \sf \big \blue{Perimeter_∆ = Side_1 + Side_2 + Side_3}[/tex]
[tex] \sf \big Perimeter_∆ = (2x² + 7) + (3x² - 2x) + (x² + 12x - 5)[/tex]
[tex] \sf \big Perimeter_∆ = 2x² + 7 + 3x² - 2x + x² + 12x - 5[/tex]
[tex] \sf \big Perimeter_∆ = 2x² + 3x² + x² + 12x - 2x + 7 - 5[/tex]
[tex] \sf \big Perimeter_∆ = 6x² + 10x + 2[/tex]
[tex] \sf \large \purple{Perimeter_∆ = 2(3x² + 5x + 1)}[/tex]
Final Answer:
[tex]\tt \Large » \: \purple{Perimeter_∆ = 2(3x² + 5x + 1) cm}[/tex]
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