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the area of the recrangle is 3×^2+7×-6,what is tje length if width is (×+3)​

Sagot :

Answer:

[tex]3x - 2[/tex]

Step-by-step explanation:

The factor of the area is

[tex]3 {x}^{2} + 7x - 6 = (3x - 2)(x + 3)[/tex]

Therefore, if the width is (x+3) then (3x-3) is the length.