Answer:
1) y=3x where x= - 3
Substitute x=3
sa given na y=3x, palitan mu yung "x" ng "-3".
so, y=3( - 3)
"negative" multiply mo sa positive number, magiging negative, kaya magiging y=-9
2)
[tex]x = {4y}^{2} [/tex]
[tex]4 {y}^{2} same \: lng \: sya \: sa \: 4(y)(y) \: kasi \: naka \: squared \\ \: yung \: y. \: pero \: kapag \: \\ {y}^{3} magiging \: (y)(y)(y) \: kasinaka \: raise \: to \: 3[/tex]
balik sa equaion:
[tex]x = 4 {y}^{2} \\ = 4(y)(y) \\ \\ but \: y = 2 \\ \\ substitute \\ \\ magiging \\ \\ x = (4)(2)(2) \\ \\ solve. \: we \: have \: x = 16[/tex]
try mu yung 3 and 4. same concept.
sana nakatulong.
